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(2t+2t^-2)/(2t-2t^-2)=0
Domain of the equation: (2t-2t^-2)!=0We multiply all the terms by the denominator
We move all terms containing t to the left, all other terms to the right
2t-2t^!=2
t∈R
(2t+2t^-2)=0
We get rid of parentheses
2t+2t^-2=0
We add all the numbers together, and all the variables
4t-2=0
We move all terms containing t to the left, all other terms to the right
4t=2
t=2/4
t=1/2
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